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The third of 4 skills relating to logarithms requires using logs since they cannot be re-expressed with the same base. Bases are NOT equal and can not be re-expressed. If 5x = 9y and since 5 & 9 cannot be re-expressed withthe same base, logs must be used. In oher words in this case: x ≠ y The solution starts like this Solving Exponential Equations 5x = 9y log5x = log9y x•log5 = y•log9 take log of both sides bring power down Example #1: log15x = log94x•log15 = log94x•1.176 = 1.973 x = 1.68 1.176 1.176 Solving Exponential Equations take log of both sides bring power down estimate logs in your calculator use algebra to solve for x Example #2: 14m-8 + 2 = 100 - 2 - 2 14m-8 = 98log14m-8 = log98(m-8)•log14 = log98(m-8)•(1.146) = 1.991 Solving Exponential Equations use algebra to isolatethe exponential take log of both sides bring power down estimate logs in your calculator use algebra to solve for x (m-8)•(1.146) = 1.991 1.146 m - 8 = 1.74 + 8 + 8 m = 9.74 1.146 Solve for b. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for x. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for x. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for p. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for x. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for n. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for m. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for n. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for n. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve Solve for v. Answer: Round to hundredths (ie. 2.34 or 0.63 or -2.00) Solving Exponential Equations use algebra to isolate exponentialtake logs of both sidesbring power downestimate logsuse algebra to solve |