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GEO: 11-3 QC (sector area & arc length)
Συνεισφορά από: Maynard
(Αρχικός συντάκτης: Dilaura)
11.3
1. Find the length of the arcs to the nearest tenth.
5 in
arc BC = 
arc CDB =
in.
in.
11.3
2. Find the length of the arcs below.    Round to the nearest tenth.
8 cm
arc BC = 
arc DB =
cm
cm
3. Find the arc lengths below if the radius = 3 feet. Round answers to the nearest tenth.
11.3
95o
3 ft.
arc DFE =
arc EB =
ft.
ft.
4. Find the arc lengths below if the radius = 3 feet. Round answers to the nearest tenth.
11.3
95o
3 ft.
arc BEF =
arc DF =
ft.
ft.
5. Find the length of the arcs below.    Round to the nearest tenth.
11.3
8 cm
arc CD =
arc BCD =
cm
cm
6. Identify the different parts of the circle    by dragging the correct labels to their correct    locations.
11.3
segment of
a circle
?
sector of
a circle
?
arc of a circle
?
7. Find the area of the orange sector.  Leave     
    your answer in terms of π.
11.3
100o
6 in
area of sector =
π in2
8. Find the area of the orange sector.  Leave your 
    answer in terms of π and round to the nearest tenth.
11.3
48o
4 in
area of sector =
π in2
9. Find the area of sector BAC. Round your answer to     the nearest tenth.
11.3
diameter = 16 ft
area of sector =
ft2
10. Find the area of sector BAD. If circle A has a circumference of 20π ft. Round your answer to the nearest tenth.
Circumference = 20π ft
area of sector =
ft2
11. Find the area of the shaded sector.       Round your answer to the nearest tenth.
11.3
7 in
area of sector =
in2
11.3
12. Find the area of the shaded segment.       Round to the nearest tenth.
5 cm
Area of segment =
cm2
11.3
13. Find the area of the shaded segment.       Round to the nearest tenth.
9 ft
Area of segment =
ft2
11.3
14. Find the area of the shaded segment of the circle      with a circumference of 16π inches.       Round to the nearest tenth.
Circumference = 16π in
Area of segment =
in2
15. Given the radius = 7.  Find the area of the shaded segment.  Round to the nearest tenth.
11.3
h = 3.5
r = 7
CB =12 cm
Area of segment =
note: the central 
angle = 120 degrees
cm2
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