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Determina los lados del triángulo x+2 ? x+1 ? x ? x + x + 1 = x+2 x2+(x+2)2= (x+1)2 x2+(x+1)2= (x+2)2 Determina los lados del triángulo x+2 x+1 x x2+(x+1)2= (x+2)2 x2 + x2 + 1 = x2+4 x2 + x2 +2x+ 2 = x2+4x+4 x2 + x2 +2x+ 1 = x2+8x+4 x2 + x2 +2x+ 1 = x2+4x+4 x2 + x2 +2x+ 1 = x2+4x+4 x2+(x+1)2= (x+2)2 x2 +6x+5 = 0 x2 -6x-5 = 0 x2 -2x- 3 = 0 2x2 +6x+6 = 0 2x2 -2x- 2 = 0 x2 + x2 +2x+ 1 = x2+4x+4 x2 -2x- 3 = 0 x2+(x+1)2= (x+2)2 x = x+1 = x+2 = un lado mida -1 metro ? La solución de x = -1 ? la rechazamos; ? no tiene sentido que ? |