- 1. Al simplificar [(2x4h3k2)*(30km4)]/{(10km)*(24h2k)}, se tiene:
A) 2h2mk
B) hmk
C) 2hm
D) 2hkm
- 2. Al simplificar [(x2/3y2)/(2x/y3)], se tiene:
A) (x2y/3)
B) (y/6)
C) (xy/6)
D) (xy2/6)
- 3. Al simplificar [(3a2/5x2)/(a2b3)] ,se tiene:
A) (1/5b2x3)
B) (3/5b2x2)
C) (3/5b3x3)
D) (2/b2x2)
- 4. Al simplificar [(5m2/7n3)/(10m4/14an4)] tenemos:
A) (a/m3)
B) (n/m2)
C) (an/m2)
D) (1/m2)
- 5. El resultado de [(6a2x3)/(a2x/5] es:
A) 15x2
B) 30x4
C) 10x2
D) 30x2
- 6. Al simplificar [(15m2/19ax3)/(20y2/38a3x4)] tenemos:
A) (a2mx/y2)
B) (a2m2x/3y2)
C) (6a3m2x/2y2)
D) (3a2m2x/2y2)
- 7. Al simplificar [(x-1)/3/(2x-2)/6] tenemos:
A) 2
B) 1
C) 1/2
D) (x-1)
- 8. Al simplificar [(3a2/a2+6ab+9b2)/(5a3/a2b+3ab2)] tenemos:
A) 3b/5(a+3b)
B) 3/5(a2+3b)
C) b/(a+3b)
D) 3/5
- 9. Al simplificar [(x3-x)/(2x2+6x)]/{(5x2-5x)/(2x+6)} tenemos:
A) x/5(x+1)
B) (x+1)/5x
C) 5x/(x+1)
D) (x-1)/5x
- 10. Al simplificar [1/(a2-30)]/{2/(a2+a-42)} tenemos:
A) (a+6)/2(a+4)
B) (a+7)/2(a-5)
C) (a+7)/2(a+5)
D) (a-7)/2(a-5)
- 11. Al simplificar [(20x2-30x)/(15x3+15x2)]/{(4x-6)/(x+1)} tenemos:
A) 2/3x
B) 1/3x
C) 3x
D) 1*3x2
- 12. Al simplificar [(a2-6a+5)/(a2-15a+56)]/{(a2+2a-35)/(a2-5a-24)} tenemos:
A) (a+3)(a-1)/(a2-81)
B) (a+3)(a-1)/(a-7)(a+7)
C) (a+3)2/(a-7)(a+7)
D) (a-3)(a+1)/(a+7)(a-7)
- 13. Al simplificar [(8x2-26x+15)/(16x2-9)]/{(6x2+13x-5)/(9x2-1)} tenemos:
A) (x+1)/(x-3)
B) (4x+3)/(2x+1)
C) (3x+1)/(4x-3)
D) (3x-1)/(4x+3)
- 14. Al simplificar {[(64a2-81b2)/(x2-81)]*[(x-9)2/(8a-9b)]}/[(8a2+9ab)/(x+9)2] tenemos:
A) (x-9)/a
B) (x+9)(x-9)/a
C) (x+9)(x+9)/a2
D) (x2-81)
- 15. Al simplificar {[(x2-x-12)/(x2-49)]*[(x2-x-56)/(x2+x-20)]}/[(x2-5x-24)/(x+5)] tenemos:
A) 1/x-7
B) 2/x-7
C) x-7
D) (x-7)/2
- 16. Al simplificar {[(a2-8a+7)/(a2-11a+30)]*[(a2-36)/(a2-1)]}/[(a2-a-42)/(a2-4a-5)] tenemos:
A) 2
B) 1/2
C) (a-1)
D) 1
- 17. Al simplificar {[(x4-27x)/(x2+7x-30)]*[(x2+20x+100)/(x3+3x2+9x)]}/[(x2-100)/(x-3)] tenemos:
A) (x-10)/(x-3)
B) x/(x-10)
C) (x-3)
D) (x-3)/(x-10)
- 18. Al simplificar {[(a2+1)/(3a-6)]/{[(a3+a)/(6a-12)]*[(4x+8)/(x-3)]} tenemos:
A) 2a(x-3)/(x+2)
B) (x-3)/2a(x+2)
C) (x+3)/2a(x-2)
D) 2a(x+2)/(x-3)
- 19. Al simplificar {[(8x2-10x-3)/(6x2+13x+6)]*[(4x2-9)/(3x2+2x)]}/[(8x2+14x+3)/(9x2+12x+4)] tenemos:
A) (2x2-3)2)/x(2x+3)
B) (2x-3)2)/x(2x+3)
C) (2x-3))/x(2x+3)
D) 2/x(2x+3)
- 20. Al simplificar [(a2-5a)/(b+b2)]/{[(a2+6a-55)/(b2-1)]*[(ax+3a)/(ab2+11b2)]} tenemos:
A) (b2+b)/(x+3)
B) (b-1)/(x+3)
C) 1)/(x+3)
D) (b(b-1)/(x+3)
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