|
Determina los lados del triángulo x+4 ? x+2 ? x ? x + x + 2 = x+4 x2+(x+4)2= (x+2)2 x2+(x+2)2= (x+4)2 Determina los lados del triángulo x+4 x+2 x x2+(x+2)2= (x+4)2 x2 + x2 + 4 = x2+16 x2 + x2 +4x+ 2 = x2+8x+16 x2 + x2 +2x+ 1 = x2+8x+4 x2 + x2 +4x+ 4 = x2+8x+16 x2 + x2 +4x+ 4 = x2+8x+16 x2+(x+2)2= (x+4)2 x2 +12x+20 = 0 x2 -12x-20 = 0 x2 -4x- 12 = 0 2x2 +6x+6 = 0 2x2 -2x- 12 = 0 x2 + x2 +4x+ 4 = x2+8x+16 x2 -4x- 12 = 0 x2+(x+2)2= (x+4)2 x = x+1 = x+2 = un lado mida -1 metro ? La solución de x = -2 ? la rechazamos; ? no tiene sentido que ? |