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(mod4) pract 4 pythag--distance slope triangles
Con il contributo di: Childress
Given 2 points
Find the distance between them:
 x,y
(2,5)
(4,8)
The slope is the legs of a right trianglea2+b2=c2    The distance between the points
slope=
=
∆y∆x
d=
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y(4,7)(7,11)
The slope is the legs of a right trianglea2+b2=c2    The distance between the points
slope=
=
d=
∆y∆x
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y (5,2)(10,9)
The slope is the legs of a right trianglea2+b2=c2   The distance between the points
slope=
=
d=
∆y∆x
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y(8,3)(2,11)
The slope is the legs of a right trianglea2+b2=c2   The distance between the points
slope=
=
∆y∆x
d=
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y(  5,1)(15,10)
The slope is the legs of a right trianglea2+b2=c2   The distance between the points
slope=
=
∆y∆x
d=
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y(10,6)( 5,18)
The slope is the legs of a right trianglea2+b2=c2   The distance between the points
slope=
=
d=
∆y∆x
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y( 1,2)(10,14)
The slope is the legs of a right trianglea2+b2=c2   The distance between the points
slope=
=
d=
∆y∆x
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y(10,3)( 2,18)
The slope is the legs of a right trianglea2+b2=c2   The distance between the points
slope=
=
d=
∆y∆x
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y( 6, 4)(17,13)
The slope is the legs of a right trianglea2+b2=c2   The distance between the points
slope=
=
d=
∆y∆x
=
y2-y1x2-x1
nearest 10th
=
Given 2 points
Find the distance between them:
 x,y(15,3)(1,19)
The slope is the legs of a right trianglea2+b2=c2   The distance between the points
slope=
=
d=
∆y∆x
=
y2-y1x2-x1
nearest 10th
=
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