a(is) = p% w(of) ORIGINAL PRICE $80.00 $42.00 Use the formula to solve the problems . % of Discount 15% 20% Sales Price a(is) = p% w(of) ORIGINAL PRICE $112.00 $120.00 Use the formula to solve the problems . % of Discount 80% 32% Sales Price a(is) = p% w(of) ORIGINAL PRICE $69.80 Use the formula to solve the problems . % of Discount 60% 25% Sales Price $40.00 a(is) = p% w(of) ORIGINAL PRICE Use the formula to solve the problems . % of Discount 5% 80% Sales Price $57.00 $90.00 a(is) = p% w(of) ORIGINAL PRICE Use the formula to solve the problems . % of Discount 64% 15% Sales Price $72.00 $146.54 a(is) = p% w(of) ORIGINAL PRICE $82.00 $60.00 Use the formula to solve the problems . % of Discount Sales Price $65.60 $61.75 a(is) = p% w(of) Cost to store: $50.00 Markup: 10% Selling Price Use the formula to solve the problems . a(is) = p% w(of) Cost to Store: $80.00 Markup:60% Selling Price: Use the formula to solve the problems . a(is) = p% w(of) Original Price $75.00 $18.00 $35.00 $60.00 $200.00 $55.00 Use the formula to solve the problems . % of Discount 30% 65% 15% 30% 55% 20% Sale Price a(is) = p% w(of) Original Price $75.00 ? $18.00 $60.00 ? $200.00 $35.00 $55.00 ? Use the formula to solve the problems . % of Discount 30% 65% 15% 30% 55% 20% ? Sale Price $52.50 $42.00 $6.30 ? $90.00 ? $28.00 $46.75 A) what was the selling price of the bicycle when the Mark up is 60% B) The store gives a 30% discount. What is the discounted price? a(is) = p% w(of) A store pays $120.00 for a bicycle Use the formula to solve the problems . |