AA 102- Algebra 1: Test
1) 
2) 
Write the product of each. write in simplest form.
Multiplying Fractions:
2
5
9
7
3
7
9
7
=
=
1) 
2) 
Write the product of each. write in simplest form.
Multiplying Fractions:
1
5
3
2
1
6
1
3
4
3
=
1) 
2) 
Write the quotient of each. write in simplest form.
Dividing Fractions:
9
5
5
÷
÷
1
3
6
5
=
=
1) 
2) 
Write the quotient of each. write in simplest form.
Dividing Fractions:
2
3
2
5
÷
÷
5
1
1
3
1
3
=
=
1) 
2) 
Write the sum of each. write in simplest form.
Adding Fractions:
2
3
4
3
+
+
12
5
7
2
=
=
1) 
2) 
4
Write the sum of each. write in simplest form.
Adding Fractions:
3
6
2
+
+
2
4
5
8
3
8
=
=
1) 
2) 
Write the difference of each. write in simplest form.
6
Subtracting Fractions:
8
5
1
4
1
1
2
4
5
=
=
2)
1) 12 apples to 15 oranges: 
Write each ratio as a fraction in lowest term:
Ratio
14 girls to 49 boys: 
2) 
1) $5 for 10 cans of soda.
Unit Rate:
10 yards in 2.5 minutes.
$           per can
yards per min.
Solve each proportion:
Proportions:
1) 
2)
n
6
14
2
=
=
49
m
11
22
→→→
→→→
3) What is 20 % of 360? →→→→→→
4)  what number is 54% of 650? 
1) What percent of 20 is 12?
Percent Problems:
2) 72 is what percent of 36?
→→→→
→→→
%
%
1) Find the percent of change from $25 to $36.
2) Find the percent of change from 289 yards to 762yards.
Percent of Change:
%
%
2) 7k - 21 = 4k
1) 16 - 6n = 4n - 4 
Solve each equation:
Equations With Variables on Both Sides:
→→→→→→
→→→→
k = 
n = 
Solve each equation:
1) 5(3x - 10) = 40
2)    2(5x + 10) = 8(2x - 5)
Equations with Distributive Property:
→→→→→ 
→→→→
x=
x =
Solve each inequality:
Inequalities
k < 12
k < 2
k > 12
k > 2
k - 5 > 7
Solve each inequality:
Inequalities
k < -12
k < -2
k > -12
k > 2
- k - 5 > 7
Solve each inequality:
Inequalities
k < 6
k < - 6
k > 6
k > - 6 
-2k - 5 > 7
Functions:
Determine whether this relation is a function:
(2, -3), (4, 7), (-2, 5), (2, 6)
if yes type  1if  no type  0 
Determine which graph is a function:
Functions:
type 1 or 2 in the box:
→→→
Determine which graph is a function:
Functions:
type 1 or 2 in the box:
→→→
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