Substitution/Elimination

Solving

Systems of Equation

Using

ELIMINATION

Solving

Systems of 

Equations

Using

SUBSTITUTION

First, make sure that one set of variables has
opposite coefficients.
Fill in all the blanks, then press "ok"
{
(-4) + 5y = 1
-2x - 5y = 11
-x + 5y = 1
y = 
answer
+
-2x - 5y = 11
-x + 5y = 1
(   ,    )
x = 
= 12
Solve
{
 -2x + 2y = 8
4x - 2y = 6
Answer
(     ,     )
Sometimes, you will have to multiply one of 
the equations by a number to get one set 
of "opposite variables."
{
What should you multiply the second equationby to make the x variable "opposite variables?"
3x - 4y = -1
x - 6y = -5
-6
3
-3
-4
Solve this system.
{
3x - 4y = -1
x - 6y = -5
(     ,     )
{
Solve.
3x - y = 11
5x + 3y = 9
(     ,     )
Solve.
(     ,     )
Solve.
(     ,     )
+
Solve for y.  
-6x + 21y = -24
6x -    4y =  24
the x-coordinate is
the y-coordinate is
Then solve for x.
Is (5, -2) a solution of
{
3x + 4y = 7
x - 2y = 9
Yes
No
?
Is (-1, 4) a solution of this system?
Yes
No
Solve.
(         ,         )
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