New Math 3rd Test for SS 1
  • 1. 1. Convert [[1264]]_8 to base ten
A) 629
B) 171
C) 692
D) 117
  • 2. 2. Convert [[211]]_3 to base eight
A) 26
B) 11
C) 7
D) 62
  • 3. 3. Convert 1.101 to decimal
A) 0.125
B) 1.625
C) 0.625
D) 0.25
  • 4. 4. In what base is the addition 465 + 24 + 225 = 1050?
A) 5
B) 6
C) 9
D) 7
  • 5. 5. Calculate [[212]]_3 x [[201]]_3 giving your answer as a number in base three
A) 10152
B) 11512
C) 113021
D) 121012
  • 6. 6. Evaluate 11110 ÷ 110
A) 110
B) 1100
C) 101
D) 1011
  • 7. 7. If [[34]]_5= 23_x, find x.
A) x = -16
B) x = -8
C) x = 16
D) x = 8
  • 8. 8. Simplify 0.0589 + 7.382 - 0.7953 correct to 2 decimal places.
A) 6.65
B) 8.24
C) 8.20
D) 6.64
  • 9. 9. Evaluate 6 - 36( mod 9)
A) 3
B) 6
C) 0
D) 5
  • 10. 10. Evaluate 27 x (20 x 3-2)/ 4
A) 48
B) 6
C) ⅓
D) 12
  • 11. 11. Simplify 125-2/3 x 15
A) ⅔
B) ⅗
C) 13
D) ⅚
  • 12. 12. Evaluate (3.69 x 105) ÷ (1.64 x 10-3)
A) 2.25 x 10-8
B) 2.25 x 10-2
C) 2.25x 102
D) 2.25 x 108
  • 13. 13. Express the sum of 6.03 x 106 and 2.17 x 105 in standard form.
A) 62.47 x 106
B) 6.247 x 1011
C) 624.7 x 1011
D) 6.247 x 106
  • 14. 14. Simplify (1/16) + 5 (90)
A) 7/25
B) 13
C) 3½
D) 2/3
  • 15. 15. Evaluate 2 ÷ (64/125)-⅔
A) 1 ⁷/25
B) 2 ⅛
C) 3 ½
D) 5 ⅚
  • 16. 16. Simplify 125 x 49½ x 10-1
A) 35/5
B) 3 ½
C) 6 ⅞
D) 2 ⅓
  • 17. 17. Given that 102 = 100, write the expression in logarithmic form
A) 3 = log10 100
B) 1 = log10 102
C) 100 = log10 2
D) 2 = log10 100
  • 18. 18. Simplify [[log]]_3 54 + [[log]]_3 15 - [[log]]_3 10
A) 4
B) 12
C) 5.9
D) 49
  • 19. 19. Evaluate [[log]]_10 45 + [[log]]_10 9-1 - [[log]]_10 2-1 without using table
A) 1
B) 2
C) 5
D) 10
  • 20. 20. Simplify [[log]]_10 √1000
A) 1½
B) 10
C) ⅔
D) ½
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