5 mod 12 prob dep/ind
Dependent conditions
P( red then blue)=
reduced
INDependent conditions
P( red then blue)=
reduced
INDependent conditions
P( green then black)=
reduced
Dependent conditions
P( green then black)=
reduced
INDependent conditions
P( red then green)=
reduced
Dependent conditions
P( blue then blue)=
reduced
Dependent conditions
P( red then black)=
reduced
INDependent conditions
P( red then red)=
reduced
INDependent conditions
P( [blue or green]  then black)=
reduced
Dependent conditions
P( blue then blue then blue)=
reduced
INDependent conditions
P( black then red)=
reduced
Students who took this test also took :

Created with That Quiz — the math test generation site with resources for other subject areas.