New Math 3rd Test for SS 1
- 1. 1. Convert [[1264]]_8 to base ten
A) 117
B) 692
C) 629
D) 171
- 2. 2. Convert [[211]]_3 to base eight
A) 7
B) 62
C) 11
D) 26
- 3. 3. Convert 1.101 to decimal
A) 0.25
B) 0.625
C) 0.125
D) 1.625
- 4. 4. In what base is the addition 465 + 24 + 225 = 1050?
A) 5
B) 9
C) 7
D) 6
- 5. 5. Calculate [[212]]_3 x [[201]]_3 giving your answer as a number in base three
A) 121012
B) 10152
C) 11512
D) 113021
- 6. 6. Evaluate 11110 ÷ 110
A) 1011
B) 1100
C) 110
D) 101
- 7. 7. If [[34]]_5= 23_x, find x.
A) x = -16
B) x = 8
C) x = 16
D) x = -8
- 8. 8. Simplify 0.0589 + 7.382 - 0.7953 correct to 2 decimal places.
A) 6.64
B) 8.20
C) 6.65
D) 8.24
- 9. 9. Evaluate 6 - 36( mod 9)
A) 6
B) 0
C) 3
D) 5
- 10. 10. Evaluate 27 x (20 x 3-2)/ 4-½
A) 12
B) 48
C) 6
D) ⅓
- 11. 11. Simplify 125-2/3 x 15
A) ⅚
B) 13
C) ⅗
D) ⅔
- 12. 12. Evaluate (3.69 x 105) ÷ (1.64 x 10-3)
A) 2.25 x 10-2
B) 2.25 x 10-8
C) 2.25 x 108
D) 2.25x 102
- 13. 13. Express the sum of 6.03 x 106 and 2.17 x 105 in standard form.
A) 6.247 x 1011
B) 6.247 x 106
C) 62.47 x 106
D) 624.7 x 1011
- 14. 14. Simplify (1/16)-¾ + 5 (90)
A) 7/25
B) 3½
C) 2/3
D) 13
- 15. 15. Evaluate 2 ÷ (64/125)-⅔
A) 2 ⅛
B) 5 ⅚
C) 1 ⁷/25
D) 3 ½
- 16. 16. Simplify 125⅓ x 49½ x 10-1
A) 2 ⅓
B) 6 ⅞
C) 3 ½
D) 35/5
- 17. 17. Given that 102 = 100, write the expression in logarithmic form
A) 1 = log10 102
B) 3 = log10 100
C) 2 = log10 100
D) 100 = log10 2
- 18. 18. Simplify [[log]]_3 54 + [[log]]_3 15 - [[log]]_3 10
A) 12
B) 49
C) 4
D) 5.9
- 19. 19. Evaluate [[log]]_10 45 + [[log]]_10 9-1 - [[log]]_10 2-1 without using table
A) 2
B) 1
C) 10
D) 5
- 20. 20. Simplify [[log]]_10 √1000
A) 1½
B) ⅔
C) 10
D) ½
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