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Solve Systems of Equations by Elimination 1
Contributed by: Harris
(Original author: Jarvie)

Solving Systems 

of Equations

Using ELIMINATION

First, you should make sure that one set of variables
has opposite coefficients.
Solve the system of equations by using elimination.
Fill in each blank, then hit "OK".
{
(-4) + 5y = 1
-2x - 5y = 11
-x + 5y = 1
5y = 
y = 
answer
+
-2x - 5y = 11
-x + 5y = 1
(   ,    )
x = 
= 12
+
Solve the system of equations by using elimination.
{
 -2x + 2y = 8
4x - 2y = 6
Solution:
x = 
x    =  14
(     ,     )
4(      ) – 2y = 6
4x - 2y = 6
  – 2y = 6
–2y = 
y = 
+
Solve the system of equations by using elimination.
-3x + 18y = 15
3x - 4y = -1
y
  = 
=
Solution:
3x – 4(       )= -1
(    ,    )
3x – 4y = -1
3x –         = -1
3x = 
x = 
+
First solve for y.  Then solve for x.
-6x + 21y = -24
6x -    4y =  24
the x-coordinate is
the y-coordinate is
y = 
+
{
Solve the system using eliminaton.
6x + 4y = 6
x - 4y = -13
x = 
x = 
Solution:
(    ,    )
6(      ) + 4y = 6
6x + 4y = 6
+ 4y = 6
4y = 
y = 
Congratulations! You finished the activity!
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