|
Some trinomials like x2 + 8x + 5 = 0 do not factor smoothly (the answers are not integers). When this happens, use the QUADRATIC FORMULA: The coefficient (the number in front) of x2 is "a" The coefficient (the number in front) of x is "b" QUADRATIC FORMULA: The constant (a number by itself) is "c" a x2 + x + = 0 b c a = 1 b = 8 c = 5 1 The coefficient (the number in front) of x2 is "a" The coefficient (the number in front) of x is "b" x2 + x + = 0 The constant (a number by itself) is "c" a x2 + x + = 0 8 b 5 c Plug these values into the quadratic formula Quadratic Formula: a = b = c = x2 + 15x + 26 = 0 Fill in the blanks a = b = c = Plug the a,b, and c values into the quadratic formula: - 1 15 26 x2 + 15x + 26 = 0 ∓ √ 2 Quadratic Formula: * 2 - 4 * * Quadratic Formula: a = b = c = 4x2 - 15x + 2 = 0 Fill in the blanks a = b = c = Plug the a,b, and c values into the quadratic formula: - 4 -15 2 4x2 - 15x + 2 = 0 ∓ √ 2 Quadratic Formula: * 2 - 4 * * Quadratic Formula: a = b = c = x2 + 2 = 0 Fill in the blanks a = b = c = Plug the a,b, and c values into the quadratic formula: - 1 0 2 ∓ x2 + 2 = 0 √ 2 Quadratic Formula: * 2 - 4 * * Quadratic Formula: a = b = c = 7x2 - 2x = 0 Fill in the blanks a = b = c = Plug the a,b, and c values into the quadratic formula: - 7 -2 0 ∓ 7x2 - 2x = 0 √ 2 Quadratic Formula: * 2 - 4 * * a = 1 b = 8 c = 5 1 The coefficient (the number in front) of x2 is "a" The (a number by itself) is "c" The (the number in front) of xis "b" x2 + x + = 0 coefficient ? constant ? a x2 + x + = 0 8 b 5 c quadratic ? Plug these values into the formula a = b = c = Plug the a, b and c values into the quadratic formula: - 1 8 5 1x2 +8x + 5 = 0 ∓ √ Quadratic Formula: 2 * 2 - 4 * * |