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Solving Systems by Substitution
Contributed by: Schaab
(Original author: Jarvie)

Solving

Using Substitution

Solve by substitution.  Fill in the blanks.
{
y = -2x + 1
y = 4x - 5
= 4x - 5
(
,
)
Solve the system.
{
y = 4x + 2
y = 10
Answer:
(
,
)
Is (-4, -1) a solution of
{
3x - 2y = -10
5x - 11y = -9
?
yes
no
Solve the system.
{

2x - y = 2

y = 10
Answer:
(
,
)
Solve the system.
{

4x -2y = 10

x = 4

Answer:
(
,
)
Solve the system.
{

y = -5x + 1

5x + 2y = 7

Answer:
(
,
)

(This means they

are parallel lines!)

When our variables disappear and we are left

with a false statement, the answer is "no solution".

(This means they

are completely overlapping!)

When our variables disappear and we are left

with a true statement, the answer is "infinitely many".

Infinitely many

4x - 2y = 4

y = 2x - 2

4x - 2(2x - 2) = 4

4x - 4x + 4 = 4
4 = 4
Solve the system.
{

4x -2y = 10

y =2x +5

Infinitely many

No solution

Solve the system.
{

3x+ y = 6

y =

-3x + 6

Infinitely many

No solution

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