∆x=xB–xA ∆y=yB–yA = = (-2,-17) A∙ = = ∙B(5,25) y=mx+c m= • c = • = • ∆x ∆y ( ) + c = = m= y=mx+c • c = = • • ∆x ∆y ( ) + c = = A∙ (-6,13) ∆x=xB–xA ∆y=yB–yA ∙B(10,5) = = ∆x=xB–xA (-15,2)A∙ = ∆y=yB–yA = m= y=mx+c • = c = • • ∆x ∆y ( ) + c = ∙B(25,-6) = (-2,15)A∙ m= y=mx+c • = c = • • ∆x ∆y ( ) + c = ∙B(8,-25) = (-20,12)A∙ (-15,-23)B∙ m= y=mx+c • c = • • = ∆x ∆y ( ) + c = = (-4,-15)A∙ m= y=mx+c • c = = • ∆x ∆y • ( ) + c = ∙B(12,-11) = (-8,-28)B∙ (-3,12)A∙ m= y=mx+c • c = • = • ( ) + c ∆x ∆y = = |