Calculus (Definite Integrals)

13x2dx
0

=

24xdx
0
 
=
26x2dx
0
=

f(x) = 6x+2
 
4f(x)dx
2

f(x) = –4x3–4x
 
1f(x)dx
0
=

2–15x2dx
1

=


f(x) = –24x3–15x2
 
2f(x)dx
1
=

f(x) = 15x2–8x–4
 
4f(x)dx
3
=

f(x) = –21x6–25x4–36x3–30x2+3
 
1f(x)dx
0
=

f(x) = –72x7+6x5–8x3
 
1f(x)dx
-1
=
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