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What does the first step to this solution look like? x+2 3 15=2x-1 3(x+2)=(x-3)5 3(x-3)=(x+2)5 15=(x+2)(x–3) = x–3 5 What does the first step to this solution look like? c-5 c 6c=2c-3 5c2=(c-5)(c+2) c(x-5)=(c+2)5c 6c=(c+2)(x–5) = c+2 5c Solve for x x + 8 -1 x = -2 x = 6 x = 10 x = -10 = 6 3 Solve for x -8 48 x = -2 x = 2 x = -6 x = 6 = -12 x Factor x2 - 9 (x-9)(x+1) (x-1)(x-9) (x-3)(x+3) (x-3)(x-3) Factor x2 + 2x - 15 (x-15)(x+1) (x-3)(x+5) (x-5)(x+3) (x-1)(x-15) Factor 3x2 - 9x + 15 3(x-1)(x+4) (x-1)(x-5) 3x(x+5) 3(x2 - 3x + 5) This rational expression is equal to (x+6)(x-3) (x-3)(x+6) 2(x-3)(x+6) (x+3) x2-3 1 = This rational expression is equal to (x-8)(x+7) (x+7) 4x x2 - 56 4x2 - 32 4x(x-8) = 4x(x-8)2(x+7) -1 4 Simplify this product 10 3 28 19 5 6 • 25 9 = 3•9 = 10•25 75 90 |