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Calculus (Definite Integrals)
供稿人: Sefchok

∫13x2 dx
0

=

∫24x dx
0
 
=
∫26x2 dx
0
=

f(x) = 6x+2
 
∫4f(x) dx
2

f(x) = –4x3–4x
 
∫1f(x) dx
0
=

∫2–15x2 dx
1

=


f(x) = –24x3–15x2
 
∫2f(x) dx
1
=

f(x) = 15x2–8x–4
 
∫4f(x) dx
3
=

f(x) = –21x6–25x4–36x3–30x2+3
 
∫1f(x) dx
0
=

f(x) = –72x7+6x5–8x3
 
∫1f(x) dx
-1
=
参加了这次测试的学生也参加了 :
Calculus (indefinite integrals)
Cálculo integral, integrales definidas
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